How would one go about proving that the magnitude of A equals the square root of x squared plus y squared plus z squared ( |A| = rad/(x^+y^+z^) )?
? Favorite Answer
it’s just pythagoras’ theorem. have to use it twice:
let the diagonal = f
lAl = square root of (x^+y^+z^)
In dimensions it is obvious the the magnitude of a vector (length) is the hypotenuse of a right triangle that is (x^ +y^)^.. But this is the side or another right triangle whose other side is z, and the hypotenuse of this triangle is the magnitude of a dimensional vector