# Magnitude of a vector = (x^+y^+z^)^.?

How would one go about proving that the magnitude of A equals the square root of x squared plus y squared plus z squared ( |A| = rad/(x^+y^+z^) )?

• it’s just pythagoras’ theorem. have to use it twice:

let the diagonal = f

f^=x^+y^

then

[lAl]^= f^+z^

[lAl]^= x^+y^+z^

lAl = square root of (x^+y^+z^)

• In dimensions it is obvious the the magnitude of a vector (length) is the hypotenuse of a right triangle that is (x^ +y^)^.. But this is the side or another right triangle whose other side is z, and the hypotenuse of this triangle is the magnitude of a dimensional vector

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