What is the slope-intercept form of a line passing through (-, -) that is perpendicular to the line x – y?

x – y = is a line

y = x/

y = x/, slope of this line is /

Slope of the line we want is -/ (Product of slopes of perp. lines is -)

x = – and y = –

Equation y-(-) = -/ *(x-(-))

(y+) = -(x+)

y + = -x –

y + x + = is our line

In slope intercept form (in the form y = m*x + c), y = -x/ – Answer

Lets call the line given L, so ,x-y= is L

and the line that is to be found is L

slope of a line of form ax +by+c= is -a/b

=> slope of L (m) = -(/-)

=> slope of L (m) = /

also we know that two line which are perpendicular and have slopes m and m respectively satisfy

m*m = –

hence slope of L (m)= -/

now

slope intercept form of a line is

y=mx+c

hence

y= (-/)x +c is the slope intercept from of the L

putting point (-,-) in this form as x and y

we get

c=-

hence

hence

y= (-/)x +c is the slope intercept from of the L

Slope of a given linei.e x-y is =/ =/

Equation of the line perpendicular is = -/ passing through (-,-) is

y+ =-/(x+)

y+ =-/x –

y = -/ x – ………………..Ans