What is the solution of the following system of equations?

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y=(x=3)^2-4
y= 2x+5
1. (0,4)
2. (-4,0)
3. (-4,-3) and (0,5)
4. (-3,-4) and (5,0)

✅ Answers

? Best Answer

  • did you maybe mean x-3 instead of x=3?

    (x-3)^2-4 = 2x+5
    x^2 -3x -3x +9 -4 = 2x +5
    x^2 -6x +5 = 2x +5
    x^2 -8x = 0
    x^2 -8x = 0; Quadratic equation: x = 0 & x = 8

    y = 5 & 21

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