Solve 5(2b+1)-3(b+1)

5(2b+1)-3(b+1)<7b+5
10b+5-3b-3<7b+5
7b+2<7b+5

This is true no matter what b is. So b is the entire set of real numbers

5(2b+1)-3(b+1)<7b+5
Step 1:- Expand the brackets at the L.H.S (i.e. left-hand-side) of the equation by means of multiplication, i.e. 5*2b+5*1-3*b-3*1<7b+5
Step 2:- By means of BODMAS, we’ve 10b+5-3b-3<7b+5
Step 3:- Collect like terms at the L.H.S of the equation derived from step 2, i.e. 10b-3b+5-3<7b+5 –> This will then result to 7b+2<7b+5…
Step 4:- Subract 7b & 2 from both sides of the final equation derived from step 3 in order for all terms to be grouped accordingly, i.e. 7b-7b+2-2<7b-7b+5-2 –> This will eventually result to 0<3, hence there is no solution for b.

Source(s):
Linear Algebra Involving Inequality

It cannot be solved. The final answer is 0 < 3, which is not true. No solution.

b=1