The rate constant for a first order reaction is 1.72 x 10-4 s-1 at 113°C. What is the activation energy at this temperature if the frequency factor is 1 x 1012?
104 kJ/mol
122 kJ/mol
139 kJ/mol
133 kJ/mol
116 kJ/mol
127 kJ/mol
1 Answer
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Use the Arrhenius equation to solve this problem.
k = A*e^(-Ea/RT)
Manipulate the equation to solve for activation energy, Ea.
Ea = -ln(k / A)*RT
Substitute the values you are given, make sure the units match up and that should give you the answer!
Source(s): Thermodynamics.