a man runs at a velocity of . m/s for min. when he runs up a hill, he slows at a rate of . m/s^ for . s and comes to a stop. how far did he run?
Break the problem up into two segments. The contant velocity portion and then the hill portion. Then you can add the two segments together to get total distance:
For the first part the speed is constant so you can just use:
x = v * t
x = (. m/s) * ( min * s/min)
x = m
For the second part you need to account for the deceleration. Use:
x = v*t + .at^
x = (. m/s)( s) + (.)(. m/s^)( s)^
x = . m
x + x = total distance
x + x = m + . m = m (rounded to two sig figs)
Answer
Favorite Answer
Break the problem up into two segments. The contant velocity portion and then the hill portion. Then you can add the two segments together to get total distance:
For the first part the speed is constant so you can just use:
x = v * t
x = (. m/s) * ( min * s/min)
x = m
For the second part you need to account for the deceleration. Use:
x = v*t + .at^
x = (. m/s)( s) + (.)(. m/s^)( s)^
x = . m
x + x = total distance
x + x = m + . m = m (rounded to two sig figs)