A compound has an empirical formula of C3H2O and an approximate gram-formula- weight (molecular weight) of 270.24 g/mol. What is its molecular formula?
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Divide the molecular mass of the compound (ยต) by the molecular mass (g) of the empirical formula.
Round the quotient to the closest integer.
empirical mass (g)= 12*3 + 1*2 + 16*1= 54g/mol
270.24/ 54= 5.4
rounding off, we have 5 (approx.)
Multiply the rounded number by all the subscripts, using the product as the new subscripts.
=C3H2O * 5
= C15H10O5
that is the molecular formula!
Source(s): 11th grade chemistry!
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first find the molar mass of C3H2O.
the molar mass of C3H2O is 54.04
divide 270.24 by 54.04
if you divide, the answer should be 5.
multiply 5 to all the numbers after the letters.
3*5=15
2*5=10
1*5=5
the final answer is : C15H10O5
Source(s): please give me best answer.
im an AP chemistry student and have been doing this for 2 years.