A compound has an empirical formula of C3H2O ,?

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A compound has an empirical formula of C3H2O and an approximate gram-formula- weight (molecular weight) of 270.24 g/mol. What is its molecular formula?

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  • Divide the molecular mass of the compound (µ) by the molecular mass (g) of the empirical formula.

    Round the quotient to the closest integer.

    empirical mass (g)= 12*3 + 1*2 + 16*1= 54g/mol

    270.24/ 54= 5.4

    rounding off, we have 5 (approx.)

    Multiply the rounded number by all the subscripts, using the product as the new subscripts.

    =C3H2O * 5

    = C15H10O5

    that is the molecular formula!

    Source(s): 11th grade chemistry!
    🙂

  • first find the molar mass of C3H2O.

    the molar mass of C3H2O is 54.04

    divide 270.24 by 54.04

    if you divide, the answer should be 5.

    multiply 5 to all the numbers after the letters.

    3*5=15

    2*5=10

    1*5=5

    the final answer is : C15H10O5

    Source(s): please give me best answer.
    im an AP chemistry student and have been doing this for 2 years.

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