find to the nearest degree the largest angle of a triangle with sides ,, and .?

The largest angle will be opposite the longest leg … so the largest angle is opposite the leg … call it θ

You know the three sides of the triangle … so use the law of cosines:

a² = b² + c² – bc cos A

cos A = (b² + c² – a²) / (bc)

so cos θ = (² + ² – ²) / ( * * )

θ = arccos [(² + ² – ²) / ( * * )]

θ = ° (to the nearest whole degree)