I’m supposed to solve for “x”
x – = √x + *end of square root* and then –
wouldn’t there be no solution? If I did this right, there’s no solution 🙂
✅ Answers
In early school we give the square root of as , but maths teachers actually know
that every number has two square roots; the square roots of are + and -.
There is a gentle convention that unless otherwise specified we only refer to the positive one, and if that is the convention your teacher likes then you should only accept x = as your answer.
But be aware that with the understanding above, – = √() as occurs as another possibility here.
x – = √(x + ) – add to both sides
x – = √(x + ) square both sides
(x – )^ = x^ – x + = x + then rearrange as
x^ – x – =
(x + )(x – ) =
Solution is x = + (with an awareness of x = -)
Regards – Ian
Use brackets for your later questions.
If I understood you correctly, the equation is
x – = √(x + ) –
x – = √(x + )
((x >= ))
x + = x^ – x +
x^ – x – =
(x – )(x + ) =
Two possible roots x = and x = -.
x = – is wrong beacause of the condition ((x >= ))
Hence, x = is the only solution.
ADD:
When we solve the equation of type
√( F ) = G
We usually use it’s equality to the following system:
F = G^ and G >=
undergo in concepts that the quantity of cone is (a million/) pi r^ h. they supply you the diameter, so which you will discover the radius. Now that’s a quesiton of looking the top. be conscious that the top, the radius, and the slant top make an actual triangle. the top is one leg, the radius is yet another leg, and the hypotenuse is .fifty . Use the Pythagorean Theorem to discover the top. Now plug the top and radius into the formulation for volume.