A square has vertives
D(-2,1) E(-5,1) F(-2,4) and G(-5,4). If it is dilated with the center of dilation at the origin and a scale factor of 2/3 (It’s supposed to be a fraction like 2 as the numerator and 3 as the denominator), what are the new vertices?
HOW DO I DO THIS?
✅ Answers
? Best Answer
Xn – Xc = k(Xo-Xc)
Yn – Yc = k(Yo-Yc)
Xn, Yn : New, scaled coordinates
Xo, Yo : Original coordinates
Xc, Yc : Coordinates of center of dilation
k : dilation scale factor
(Xc, Yc) = (0,0)
k = 2/3
Xn = (2/3)Xo
Yn = (2/3)Yo
D(-2,1) → (-4/3, 2/3)
E(-5,1) → (-10/3, 2/3)
F(-2,4) → (-4/3, 8/3)
G(-5,4) → (-10/3, 8/3)
multiply each coordinate by 2/3
http://img10.imageshack.us/img10/479/omo…