Solve for w? How do you figure this out?

I’m assuming 2w-12 is the denominator on the left, and w-6 is the denominator on the right.

-5/2w-12 +2 = -3/w-6

First you can see that the denominator of 2w-12 can be factorized into 2(w-6) which is the same as the one on the right hand side.

-5/2w-6 + 2 = -3/w-6

Multiplying everything by 2 to get rid of the 2 in the 2(w-6)

-5/w-6 + 4 = -6/w-6

Bring over all the terms with the w in it

-5/w-6 + 6/w-6 = -4

Simplifying

1/w-6 = -4

Multiply out the w-6

1 = 4(w-6)

Expanding the bracket

1=4w-24

Bring the 24 over

23=4w

Divide both sides by 4

23/4 = w

Hope this helps!

Source(s): Maths Graduate

-5/(2w – 12) + 2 = -3/(w – 6)

2 = 5/(2w – 12) – 3/(w – 6)

2 = 5/(2 * (w – 6)) – 3/(w – 6)

Now, multiply both sides of the equation by 2 * (w – 6)

2 * 2 * (w – 6) = 5 * 2 * (w – 6) / (2 * (w – 6)) – 3 * 2 * (w – 6) / (w – 6)

Simplify

4 * (w – 6) = 10 – 6

4 * (w – 6) = 4

w – 6 = 1

w = 7