The ionization constant (Ka) of HF is 6.7 x 10 -4. Which of the following is true in a 0.1M solution of this?

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The ionization constant (Ka) of HF is 6.7 x 10 -4. Which of the following is true in a 0.1M solution of this acid?

✅ Answers

? Best Answer

  • HF –> H+ + F-

    6.7e-4 = x * x / 0.1 – x

    6.7e-5 – 6.7e-4x – x^2 = 0

    x = 0.0078572 = [H+] and [F-]

    So Choice B

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