5) http://tinypic.com/r/2lnfnr5/5
6 & 7) http://tinypic.com/r/34t4zgo/5
Any help is much appreciated. I’m struggling to understand because I was very ill and missed a lot of school. Thank you so much in advance.
2
✅ Answers
? Favorite Answer
To look the proper way of the solved matrices below go to the link
https://docs.google.com/document/d/1B-crWeMhkeqCHS…
QUE-1
The question asks to find the product of the matrices
A = 2 3 AND B = 5
4 9 -6
Now product of AB = (2*5) + (3*-6) = 10 + (-18) = -8
(4*5) + (9*-6) 20 + (-54) -34
The correct option is A
QUE-2
A = [2 4 3] , B = 3 -6 and C = [ -9 8 ]
7 2
0 5
Thus, AB + C = [2*3 + 4*7 + 3*0, 2*-6 + 4*2 + 3*5] + [-9 , 8] = [6 + 28 +0 , -12 + 8 +15] + [-9 , 8]
=[34, 11] + [-9,8] = [34 + (-9) , 11+9] = [25 , 19]
The correct option is D
HOPE U LIKED 🙂
3. f(-5)= |-5-one million| = |-6| = 6 f(2) = |2-one million| = one million 4. f(a) = a^2 – 2a +3 f(a+h) = (a+h)^2 – 2(a+h) + 4 f(a)/h = (a^2 – 2a +3)/h f(a+h)-f(a)/h = a^2 + 2ah +h^2 -2a – 2h + 4 – (a^2 – 2a +3)/h =(a^2h + 2ah^2 + h^3 -2ah-2h^2+4h – a^2 + 2a -3)/h =(h^3 + h^2(2a-2) + h(a^2+2a+4) -a^2+2a-3)/h 5. g(-one million) = 7 g(0) = 7 g(4) = one million/4 *in line with danger a minor simplification mistake on extensive form 4, i did it solely on computing gadget and did now not particularly double verify 🙂 *