Chemistry problem! stuck for 2 hours already on this !!
You can test for the presence of chloride ions in a sample of water by adding silver nitrate, AgNO3. What mass of solid calcium chloride, AgCl2(s) will precipitate from a solution that contains 1.50 g of calcium chloride, CaCl 2 (s) if an excess amount of silver nitrate is present.
The balanced equation is:
CaCl2(s) +2AgNO3(aq) = 2AgCl(s) + Ca(NO3)s(aq)
I have tried so hard to figure this out and my formulas aren’t getting the right answers, please explain so I can use learn! thank you!
✅ Answers
Answerer 1
First you confused me. You are asking for calcium chloride, but listed silver chloride. I assume that was a mistake.
So first thing first. FIND MOLS. That should always be engraved in your mind with these problems. The problem states that AgNO3 is the excess reactant and CaCl2 is the limited reactant
1.5g/110.98g= .0135 mols of CaCl2
We know that for every mol of CaCl2 there is 2 mols of AgNO3
AgCl2 mols = .027mols then times this number by amu of AgCl2 or 143.32g/mol
3.87 grams
Dimensional Analysis way: 1.5g x 1 mol/ 110/98g x 2mol AgCl2/ 1 mol CaCl2 x 143g/1mol AgCl2= 3.87 grams