CHEMISTRY QUESTION: Assuming a 60% yield can be expected, what is the max no. of 75cm^3 that can be collected?

C2H5OH (alcohol) + Al2O3 catalyst goes to C2H4 (ethene) + H2O

when ethanol is converted to ethene a 60% yield can be expected. Assuming this yield, what is the maximum number of 75cm^3 test tubes of ethene that could be collected at room teperature and pressure when 2.4cm^3 of ethanol, density 0.8cm^-3 , react?

could someone please help me understand how to do this question?

1 Answer

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  • C2H5OH → C2H4 + H2O

    Supposing the missing unit on the density of ethanol to be “grams”:

    (2.4 cm^3 C2H5OH) x (0.8 g·cm^-3) / (46.06867 g C2H5OH/mol) x

    (1 mol C2H4 / 1 mol C2H5OH) x (0.60) = 0.02501 mol C2H4

    Supposing room temperature to be 25°C:

    (0.02501 mol) x (22.414 L/mol) x (25 + 273) / (0 + 273) = 0.6119 L at 25°C

    (611.9 mL) / (75 ml/test tube) = 8 (and a small fraction) test tubes

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