Silver sulfide (Ag2S) is the common tarnish on silver objects. What weight of silver sulfide can be made from 1.23 mg of hydrogen sulfide (H2S) obtained from a rotten egg? The reaction of formation of silver sulfide is given below:
Ag(s) + H2S(g) + O2(g) Ag2S(s) + H2O(l) (Equation must first be balanced.)
If you could please explain how to solve this problem, it would help me out a lot. Thank you.
✅ Answers
? Best Answer
1.23 mg is .123 g
.123g H2S * 1 mole H2S/ mass of 1 mole H2S * 2 mole H2S/2 mole Ag2S * 1mole Ag2S/ mass of 1 mole Ag2S
So take .123g multiply it by 2 and then the mass of the Ag2S. then divide that by mass of H2S, 2, and youre done. but multiply mass of H2S and two before dividing**