Probabilities~~~~~~~~~~~~~~~~~…

Bag A contains 7 red balls,and 5 blue balls.Bag B contains 5 red balls and 4 green balls.One ball is randomly drawn from A and put into bag B.Then one ball is drawn from bag B randomly and put into A.Final,a ball is drawn from A at random.Find the probability that the final ball drawn from bag A is
(i)blue
(ii)red

✅ Answers

? Best Answer

  • (i) blue => (7/12) * (5/12) + (5/12) * (1/10) * (5/12) + (5/12) * (9/10) * (4/12) = 0.3854166667

    The probability of final ball drawn from bag A is green can be easily worked out by (4/10) * (1/12) = 0.0333333333

    (ii) so we can now work out the remaining probability by subtraction, therefore for
    red => 1 – 0.033333333 – 0.385416667 = 0.5812499997

    It would be quite long to explain where I got the numbers from from (i) to work out, so I just hope you can cope with it.

    Hope this helps.

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