the pressure in a 22.4 L vessel containing 1. mol of neon gas at 1 degrees C what in atm?

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Using the van der Waals equation.

I think I have the correct answer. I just need confirmation.

Update:

Is the answer 1.37?

1 Answer

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  • Van der Waal’s equation

    P + n2a/V2)(V – nb) = nRT

    for neon

    a=0.208 bar L^2 /mol^2 and b=0.0167 L/mol

    Substituting given values into the equation

    {P + (0.208 bar L^2 )/22.4 L^2)} (22.4-0.0167 L)= 8.314 L bar K−1 mol−1×10−2 * 373 K

    P= 1.37 bar

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