Why is the empirical formula experiment of magnesium oxide is not suitable to copper (II) oxide?

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  • The usual method of determining the empirical formula of MgO is to ignite a sample of Mg of known mass . Mg is very reactive and it will easily ignite to form the oxide. Determine mass of the oxide. You now have sufficient data to get the mass of Mg and O reacted. Hence determine the empirical formula

    Copper is an non-reactive metal . You can heat a sample of copper all day and it will not produce any oxide. Therefore you cannot use the above method for Mg for Cu.

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